Question

In: Statistics and Probability

Assume that both populations are normally distributed. ​(a) Test whether mu 1 not equals mu 2μ1≠μ2...

Assume that both populations are normally distributed.

​(a) Test whether

mu 1 not equals mu 2μ1≠μ2

at the

alpha equals 0.01α=0.01

level of significance for the given sample data.​(b) Construct a

99​%

confidence interval about

mu 1 minus mu 2μ1−μ2.

Population 1

Population 2

n

13

13

x overbarx

13.9

11.2

s

3.1

2.8

Solutions

Expert Solution

i am using minitab to solve the problem.

Summarized data ;-

copy the data in minitab stat basic statistics 2 sample t select summarized data in sample 1 type13 in sample size, 13.90 in sample mean, 3.10 in standard deviation in sample 2 type 13 in sample size, 11.2 in sample mean, 2.80 in standard deviation options in confidence level type 99 in hypothesized difference type 0 select the alternative hypothesis as difference hypothesized difference ok ok.

*** SOLUTION ***

a).hypothesis:-

[ claim ]

the test statistic (z) = 2.33

p value = 0.0289

decision:-

p value = 0.0289 > 0.01(alpha)

we fail to reject the null hypothesis.

b).the 99% confidence interval = (-0.55 , 5.95)

*** if you have any doubt regarding the problem ,please write it in the comment box...if satisfied,please UPVOTE.


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