In: Statistics and Probability
Assume that both populations are normally distributed. (a) Test whethermu 1 not equals mu 2μ1≠μ2 at thealpha equals 0.01α=0.01 level of significance for the given sample data.(b) Construct a99% confidence interval aboutmu 1 minus mu 2μ1−μ2. |
Population 1 |
Population 2 |
|||
---|---|---|---|---|---|
n |
13 |
13 |
|||
x overbarx |
13.9 |
11.2 |
|||
s |
3.1 |
2.8 |
i am using minitab to solve the problem.
Summarized data ;-
copy the data in minitab stat basic statistics 2 sample t select summarized data in sample 1 type13 in sample size, 13.90 in sample mean, 3.10 in standard deviation in sample 2 type 13 in sample size, 11.2 in sample mean, 2.80 in standard deviation options in confidence level type 99 in hypothesized difference type 0 select the alternative hypothesis as difference hypothesized difference ok ok.
*** SOLUTION ***
a).hypothesis:-
[ claim ]
the test statistic (z) = 2.33
p value = 0.0289
decision:-
p value = 0.0289 > 0.01(alpha)
we fail to reject the null hypothesis.
b).the 99% confidence interval = (-0.55 , 5.95)
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