In: Statistics and Probability
Assume that both populations are normally distributed. a) Test whether 2μ1≠μ2 at the α=0.05 level of significance for the given sample data. b) Construct a 95% confidence interval about 2μ1−μ2. |
Sample 1 |
Sample 2 |
|||
---|---|---|---|---|---|
n |
19 |
19 |
|||
x overbarx |
11.7 |
14.4 |
|||
s |
3.4 |
3.9 |
|||
SOLUTION:
From given data,
Assume that both populations are normally distributed
Sample 1 | Sample 2 | |
= 19 | = 19 | |
=11.7 | = 14.4 | |
= 3.4 | = 3.9 |
a) Test whether 2μ1≠μ2 at the α=0.05 level of significance for the given sample data
H0 : 2μ1 = μ2 ( Null hypothesis )
H1 : 2μ1 ≠ μ2 ( Alternative hypothesis )
- = 11.7 - 14.4 = -2.7
SE( - ) =
=
= 1.18699
Test statistic : t = ( - ) / SE( - )
= -2.7 / 1.18699
= - 2.2746
t = - 2.2746
degree of freedom =df = + - 2 = 19 + 19 -2 = 36
α=0.05 = > critical value = tcritical = 2.028
b) Construct a 95% confidence interval about 2μ1−μ2
95% confidence interval is
( - ) tcritical * SE( - )
- 2.7 2.028 * 1.18699
- 2.7 2.407215
( - 2.7 - 2.407215 ) , ( - 2.7+ 2.407215 )
-5.1072 , -0.2927
confidence interval about 2μ1−μ2 is from -5.10 to -0.29