If 4 moles of oxygen and 2 moles of nitrogen gas occupy 12 liters at a...

If 4 moles of oxygen and 2 moles of nitrogen gas occupy 12 liters at a total pressure of 6 Atm, the partial pressure of oxygen gas in the container is?

Solutions

Expert Solution

mole fraction of oxygen = no.of moles of oxygen /(no.of moles of oxygen +no.of mole of nitrogen)

= 4/(4+2)

= 4/6

= 0.67

partialpressure of oxygen = total pressure * mole fraction of oxygen = 6*0.67 = 4.02 atm

queen_honey_blossom answered 1 year ago

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