2NO (g) + O2 (g) -> 2 NO2 (g) if 12 moles of nitrogen monoxide are...

2NO (g) + O2 (g) -> 2 NO2 (g)
if 12 moles of nitrogen monoxide are combined with 10 moles of oxygen, how many moles of NO2 should form? I need step by step to help with my test Please type if possible.

Expert Solution

Well, we can say that the chemical equation is :

NO + O2 --> NO2

Given reaction is

2NO + O₂ --> 2NO₂

Given quantity of reactants 12 moles of NO

10 moles of O₂.

limiting reagent (the one that we'll run out of first).

The stoichiometric ratios for NO:O₂:NO₂ are, from our equation, 2:1:2. Look at it this way:

For all 12 moles of NO to react, we'll need half as many in moles of O2--that is, we'll need 6 moles of O2. Since we have more than 6 moles of O2, this means O2 is in excess, and NO is the limiting reagent.

So we get that all 12 moles of NO will react with 6 of the moles of O2 and produce 12 moles NO2. I'm not sure why your answer is supposed to be 5, as it just isn't true.

queen_honey_blossom answered 2 years ago

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