Consider the following three-step mechanism for a reaction: Br2 (g) ⇌ 2 Br (g) Fast Br...

Consider the following three-step mechanism for a reaction:
Br₂ (g) ⇌ 2 Br (g) Fast
Br (g) + CHBr₃ (g) → HBr (g) + CBr₃ (g) Slow
Br (g) + CBr₃ (g) → CBr₄ (g) Fast

Based on this mechanism, determine the rate law for the overall reaction.

Rate =

Expert Solution

Using the three step mechanism for the given reaction

, the slowest step is the rate determing step for the reaction shown

whereas the fast step are not the rate determining step, so the rate law for the given mechanism can be stated as

Rate = [CHBr3][Br]

queen_honey_blossom answered 2 years ago

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Consider the following three-step mechanism for a reaction: Br2 (g) ⇌ 2 Br (g) Fast Br...

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