Question

In: Chemistry

PART A.Identify the proper form of the equilibrium-constant expression for the equation N2(g)+O2(g)⇌2NO(g) 1.K=[NO][N2][O2] 2.K=[NO]2[N2][O2] 3.K=[N2][O2][NO]2...

PART A.Identify the proper form of the equilibrium-constant expression for the equation

N2(g)+O2(g)⇌2NO(g)

1.K=[NO][N2][O2]
2.K=[NO]2[N2][O2]
3.K=[N2][O2][NO]2
4.K=2[NO][N2][O2]

PART B. The equilibrium-constant of the reaction

NO2(g)+NO3(g)⇌N2O5(g)

is K=2.1×10−20. What can be said about this reaction?

1.At equilibrium the concentration of products and reactants is about the same.

2.At equilibrium the concentration of products is much greater than the concentration of reactants.

3.At equilibrium the concentration of reactants is much greater than that of products.

4.There are no reactants left over once the reaction reaches equilibrium.

Part C

The acid HOCl (hypochlorous acid) is produced by bubbling chlorine gas through a suspension of solid mercury(II) oxide particles in liquid water according to the equation

2HgO(s)+H2O(l)+2Cl2(g)⇌2HOCl(aq)+HgO⋅HgCl2(s)

What is the equilibrium-constant expression for this reaction?

1.K=[Cl2]2[HOCl]2
2.K=[HOCl]2[HgO⋅HgCl2][Cl2]2[H2O][HgO]2
3.K=[HOCl]2[Cl2]2
4.K=[HOCl]2[Cl2]2[H2O]

Solutions

Expert Solution

For a reaction with the form:

aA + bB → cC + dD

Equilibrium constant is the relationship of products and reactants expressed like this

K = [A]a [B]b / ( [C]c[D]d )

K is the equilibrium constant

Part A

products 2NO

reactants N2 and O2

Equilibrium consttant = products / reactants

Equilibrium constant = [NO]2 / [N2 ] [O2]

Part B

The equilibrium constant is the ratio of products to reactants

if the products concentration is higher than the reactants the K constant is higher than 1

if reactants concentration is higher than that of products then k constant is < 1

since the K constant given is less than 1 then

Answer is 3.At equilibrium the concentration of reactants is much greater than that of products.

Part C

2HgO(s)+H2O(l)+2Cl2(g)⇌2HOCl(aq)+HgO⋅HgCl2(s)

K constant = HOCl2 / (Cl2)2

this is because at equilibrium the concentration of liquids and solids is equal to 1.

*if this answer is helpful dont forget to rate it =)


Related Solutions

Consider the equilibrium N2(g) + O2(g) ⇄ 2 NO(g) At 2300 K the equilibrium constant K...
Consider the equilibrium N2(g) + O2(g) ⇄ 2 NO(g) At 2300 K the equilibrium constant K = 1.7 × 10-3. Suppose that 0.0150 mol NO(g), 0.250 mol N2(g), and 0.250 mol O2(g) are placed into a 10.0-L flask and heated to 2300 K. The system is not at equilibrium. Determine the direction the reaction must proceed to reach equilibrium and the final equilibrium concentrations of each species. to the right to the left [N2] =____ mol/L [O2] = ____mol/L [NO]...
At 2000 ∘C the equilibrium constant for the reaction 2NO(g)←−→N2(g)+O2(g) is Kc=2.4×103. The initial concentration of...
At 2000 ∘C the equilibrium constant for the reaction 2NO(g)←−→N2(g)+O2(g) is Kc=2.4×103. The initial concentration of NO is 0.250 M . Part A What is the equilibrium concentration of NO? Part B What is the equilibrium concentration of N2? Part C What is the equilibrium concentration of O2? Please show me how to got your results :) Thank you!
Consider the equilibrium N2(g)+O2(g)+Br2(g)⇌2NOBr(g) Part A Calculate the equilibrium constant Kp for this reaction, given the...
Consider the equilibrium N2(g)+O2(g)+Br2(g)⇌2NOBr(g) Part A Calculate the equilibrium constant Kp for this reaction, given the following information (at 295 K ): 2NO(g)+Br2(g)⇌2NOBr(g)Kc=2.1 2NO(g)⇌N2(g)+O2(g)Kc=2.2×1030 Express your answer using two significant figures.
At 3748°C, K = 0.093 for the following reaction. N2(g) + O2(g) equilibrium reaction arrow 2...
At 3748°C, K = 0.093 for the following reaction. N2(g) + O2(g) equilibrium reaction arrow 2 NO(g) Calculate the concentrations of all species at equilibrium for each of the following cases. (a) 1.6 g N2 and 3.0 g O2 are mixed in a 1.3-L flask. (b) 2.0 mol pure NO is placed in a 2.1-L flask.
Q1)Determine the equilibrium constant for the following reaction at 498 K. 2 Hg(g) + O2(g) →...
Q1)Determine the equilibrium constant for the following reaction at 498 K. 2 Hg(g) + O2(g) → 2 HgO(s) ΔH° = -304.2 kJ; ΔS° = -414.2 J/K a)1.87 × 1010 b)2.31 × 10-22 c)4.33 × 1021 d)8.10 × 1031 e)5.34 × 10-11 Q2) Determine the equilibrium constant for the following reaction at 655 K. HCN(g) + 2 H2(g) → CH3NH2(g) ΔH° = -158 kJ; ΔS°= -219.9 J/K a)2.51 × 10-13 b)3.99 × 1012 c)3.26 × 10-12 d)13.0 e)3.07 × 1011
For the equilibrium 2NO2(g) ⇌ 2NO(g) + O2(g), Kp = 2.0 × 10-2 at 365oC. Suppose...
For the equilibrium 2NO2(g) ⇌ 2NO(g) + O2(g), Kp = 2.0 × 10-2 at 365oC. Suppose 0.0600 mol NO(g), 0.0150 mol O2(g), and 1.60 mol NO2(g) are added to a rigid 2.00-L flask. What is ΔG?
At a particular temperature Kp = 0.041 for the reaction N2(g) + O2(g) ⇄ 2NO(g) What...
At a particular temperature Kp = 0.041 for the reaction N2(g) + O2(g) ⇄ 2NO(g) What is the equilibrium partial pressure of NO if a flask initially contains 0.12 atm of all three gases? Report the pressure of NO in atm rounded to the nearest hundredth of an atm.
Consider the following reaction at 173 K: 2 N2O (g) → 2 N2 (g) + O2...
Consider the following reaction at 173 K: 2 N2O (g) → 2 N2 (g) + O2 (g) In one of your laboratory experiments, you determine the equilibrium constant for this process, at 173 K, is 6.678E+57. You are given a table of data that indicates the standard heat of formation (ΔHoform) of N2O is 82.0 kJ/mol. Based on this information, what is the standard entropy change (ΔSorxn) for this reaction at 173 K? ΔSorxn(J/K)=
The Equilibrium-Constant Expression Learning Goal: To understand the form and meaning of the equilibrium-constant expression. Chemical...
The Equilibrium-Constant Expression Learning Goal: To understand the form and meaning of the equilibrium-constant expression. Chemical reactions are usually not one-way trips from reactant to product. In fact, most chemical reactions are reversible to at least some extent. Products formed by the forward reaction may react with each other to regenerate the reactants. When reactants are mixed, they will begin to react at a forward reaction rate particular to that chemical reaction. As reactants are depleted and products are formed,...
1 Write a balanced equilibrium equation and equilibrium constant expression for the dissolution of Ca(OH)2(s). 2....
1 Write a balanced equilibrium equation and equilibrium constant expression for the dissolution of Ca(OH)2(s). 2. If a compound is only slightly soluble, will the equilibrium lie “to the left” or “to the right” if the equation is written with solid on the left and the ions on the right? 3. Will the equilibrium constant (Ksp) be large or small for the reaction in question number 2?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT