In: Chemistry
For the equilibrium 2NO2(g) ⇌ 2NO(g) + O2(g), Kp = 2.0 × 10-2 at 365oC. Suppose 0.0600 mol NO(g), 0.0150 mol O2(g), and 1.60 mol NO2(g) are added to a rigid 2.00-L flask. What is ΔG?
molarity of NO = 0.06 / 2 = 0.03 M
molarity 0f O2 = 0.015 / 2 = 0.0075 M
molarity of NO2 = 1.60 / 2 = 0.8 M
Kp = Kc (RT)^Dn
2 x 10^-2 = Kc x (0.0821 x 638)^1
Kc = 3.82 x 10^-4
ΔGo = - RT ln Kc
= - 8.314 x 10^-3 x 638 x ln (3.82 x 10^-4)
= 41.75 kJ/mol
2NO2(g) <-----------------> 2NO(g) + O2(g)
0.8 0.03 0.0075
Qp = [NO]^2[O2] / [NO2]^2
= 0.03^2 x 0.0075 / 0.8^2
= 1.05 x 10^-5
ΔG = ΔGo + RT ln Qp
= 41.75 + 8.314 x 10^-3 x 638 x ln (1.05 x 10^-5)
= -19 kJ/mol
ΔG = -19 kJ/mol