For the reaction: N2(g) + 2 O2(g) ↔ 2 NO2(g), Kc = 8.3 × 10-10 at...

For the reaction: N2(g) + 2 O2(g) ↔ 2 NO2(g), Kc = 8.3 × 10-10 at 25°C. What is the concentration of N2 gas at equilibrium when the concentration of NO2 is twice the concentration of O2 gas?

Expert Solution

N2(g) + 2 O2(g) ↔ 2 NO2(g)

Kc = [NO2]^2/[N2][O2]^2

[O2] = x

[NO2] = 2x

Kc = [NO2]^2/[N2][O2]^2

8.3*10^-10 = (2x)^2/[N2](x)2

8.3*10^-10 = 4x^2/[N2]*x^2

[N2] = 4/8.3*10^-10 = 4.8*10^9 M

queen_honey_blossom answered 2 years ago

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