In: Economics
The market for frogs has inverse demand p = 30 − 1/3Q. Two suppliers only operate.
Firm 1 has constant marginal cost 15 and firm 2 has constant marginal cost 10.
If the two firms compete by choosing quantities, find the equilibrium price
and profits.
If they compete in price, find the equilibrium price and profits.
What price and profits would you anticipate if they compete in quantities
and firm 1 can choose its quantity first?
Answer) p= 30-Q/3
MC1= 15
MC2= 10
Answer 1) p= 30- [ (Q1+Q2)/3 ]
Case 1) Profit maximsation for firm 1
At profit maximisation MR= MC1
MR= ∆TR1/∆Q1
TR1= p×Q1
TR1=[ 30-(Q1+Q2)/3 ] Q1
MR1 = 30 - [ (2Q1+Q2)/3 ]
•MR1= (90-2Q1-Q2)/3
• MC1=15
90-2Q1-Q2= 45
Q1=( 45-Q2)/2 -----------------(A)
Case 2) Profit maximisation for firm 2
At profit maximisation MR2= MC2
MR2=∆TR2/∆Q2
TR2= p × Q2
TR2=[ 30- (Q1+Q2)/3 ] Q2
MR2= 30 - ( Q1+ 2Q2)/3
• MR2 =( 90-Q1-2Q2)/3
• MC2= 10
So,90-Q1-2Q2= 30
(60-Q1)/2 = Q2
Q2= (60-Q1)/2 ------------(B)
Putting the value of Q1= (45-Q2)/2 in equation (B)
Q2= (60-[ (45-Q2)/2] )/ 2
Q2= (120-45+Q2)/4
4Q2= 75+Q2
•Q2*= 15
Q1*=(45-Q2)/2
•Q1*= 15
At Q1=Q2=15
Equilibrium price= p= 30-[ (Q1+Q2)/3 ]
p= 30- [ ( 30)/3]
•p= 20
•Profit of firm 1 = TR1- TC1
TR1= p× Q1
TC1= 15Q1 [ integrating MC with respect to Q1]
TR1= 20*15= 300
TC1= 15*15 = 225
Profit of firm 1= 300-225= 75
• Profit of firm 2 =TR2-TC2
TR2= p× Q2
TC2= 10Q2 ( integrating MC2 with respect to Q2)
TR2= 20* 15 = 300
TC2= 10* 15 = 150
Profit of firm 2 = 300-150= 150
Answer 2) When they compete in price
Answer c) When firm 1 choose Quantity first
p= 30- (Q1+Q2)/3
MC1= 15
MC2= 10
Step 1) Profit maximsation for firm 2 occurs at a point where MR2=MC2
MR2=∆TR2/∆Q2
TR2= p× Q2= [30- (Q1+Q2)/3] Q2
• MR2= 30 - ( Q1+ 2Q2)/3
• MC2= 10
30-( Q1+2Q2)/3= 10
90-Q1-2Q2 = 30
Q2= (60-Q1)/2 -----------(A)
Step 2) Putting the value of Q2 in p
p= 30- (Q1+Q2)/3
p= 30- (Q1 + { (60 -Q1) } /2 ) /3
p= 30 - { 2Q1+60-Q1}/6
p= (120-Q1)/6
Step 3) Maximisation of firm 1 profit occurs at a point where MR1= MC1
TR1= p* Q1
TR1=[ (120-Q1)/6 ] * Q1
MR1= (120-2Q1)/6
MC1= 15
90= 120 -2Q1
Q1= 15
Q2= (60-Q1)/2
Q2= 22.5
p= 30- ( 15+22.5) /3
p= 17.5