Question

In: Physics

An object is placed 49 cm to the left of a converging lens of focal length...

An object is placed 49 cm to the left of a converging lens of focal length 21 cm. A diverging lens of focal length − 29 cm is located 10.3 cm to the right of the first lens. (Consider the lenses as thin lenses).

a) Where is the final image with respect to the second lens?

b)What is the linear magnification of the final image?

Solutions

Expert Solution


Related Solutions

An object is placed 35.5 cm to the left of a converging lens of focal length...
An object is placed 35.5 cm to the left of a converging lens of focal length 18.8 cm. A second lens, which is diverging and has a focal length of -88.8 cm is placed at a certain distance d to the right of the first lens. A) where is the image of the object formed by the first lens and what is its magnification? B) If the distance d=53.6 cm, where is the final image of the object? What are...
A converging lens has a focal length of 15 cm. If an object is placed at...
A converging lens has a focal length of 15 cm. If an object is placed at a distance of 5 cm from the lens, a. find the image position d i = _____ cm (include sign +/-) b. find the magnification M = _____(include sign +/-) c. characterize the resulting image. ________(real or virtual) ________(enlarged or reduced) ________(upright or inverted)
a) The focal length of a converging lens is 35 cm. An object is placed 100...
a) The focal length of a converging lens is 35 cm. An object is placed 100 cm in front of the lens. Describe the image. b) The focal length of a converging lens is 35 cm. An object is placed 30 cm in front of the lens. Describe the image. c) The focal length of a diverging lens is 35 cm. An object is placed 100 cm in front of the lens. Describe the image. d) The focal length of...
A 1.00-cm-high object is placed 3.95 cm to the left of a converging lens of focal...
A 1.00-cm-high object is placed 3.95 cm to the left of a converging lens of focal length 9.00 cm. A diverging lens of focal length −16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image.
An object is 15.2 cm to the left of a lens with a focal length of...
An object is 15.2 cm to the left of a lens with a focal length of 10.2 cm. A second lens of focal length 11.8 cm is 39.27 cm to the right of the first lens. The height of the object of is 2.1 cm. What is the location of the final image with respect to the second lens? What is the height of the image?
A converging lens has a focal length of 21.1 cm. (a) Locate the object if a...
A converging lens has a focal length of 21.1 cm. (a) Locate the object if a real image is located at a distance from the lens of 63.3 cm. distance cm location (b) Locate the object if a real image is located at a distance from the lens of 105.5 cm. distance cm location (c) Locate the object if a virtual image is located at a distance from the lens of -63.3 cm. distance cm location (d) Locate the object...
1. An object is 30 cm in front of a converging lens with a focal length...
1. An object is 30 cm in front of a converging lens with a focal length of 10 cm. Use ray tracing to determine the location of the image. Is the image upright or inverted? Is it real or virtual? 2. An object is 6.0 cm in front of a converging lens with a focal length of 10 cm. Use ray tracing to determine the location of the image. Is the image upright or inverted? Is it real or virtual?...
A diverging lens of focal length -12.5 cm is placed 40.0 cm from a converging lens...
A diverging lens of focal length -12.5 cm is placed 40.0 cm from a converging lens of unknown focal length.  A 15.2 cm tall erect object is placed 25.3 cm in front of the diverging lens which is to produce an image on a screen that is twice the size of the original object but inverted. A) Where should the screen be located to produce a clear image? Give the distance from the converging lens to the screen in cm. B)...
An object 2.00 cm high is placed 30.8 cm to the left of a converging lens...
An object 2.00 cm high is placed 30.8 cm to the left of a converging lens having a focal length of 25.8 cm. A diverging lens having a focal length of −20.0 cm is placed 110 cm to the right of the converging lens. (Use the correct sign conventions for the following answers.) (a) Determine the final position and magnification of the final image. (Give the final position as the image distance from the second lens.) final position :__________ cm...
A 1.00 cm-high object is placed 3.40 cm to the left of a converging lens of...
A 1.00 cm-high object is placed 3.40 cm to the left of a converging lens of focal length 8.95 cm. A diverging lens of focal length −16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position Take the image formed by the first lens to be the object for the second lens and apply the lens equation to each lens to locate the final image. cm  ---Select--- behind the...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT