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A 1.00-cm-high object is placed 3.95 cm to the left of a converging lens of focal...

A 1.00-cm-high object is placed 3.95 cm to the left of a converging lens of focal length 9.00 cm. A diverging lens of focal length −16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image.

Solutions

Expert Solution

Height of object

Distance of object from converging lens ,focal length of converging lens

focal length of diverging lens , distance between two lenses

For converging lens, using thin lens formula

First image is formed at distance to the left of converging lens

This image acts as an object to diverging lens

New object distance

For diverging lens, using thin lens formula

Final image is formed at a distance to the left of diverging lens.

Position of final image is to the left of diverging lens. or to the left of converging lens.

Magnification of final image is

Height of final image is

genius_generous answered 1 month ago

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