Question

In: Chemistry

A solid mixture consists of 51.0 g of KNO3 (potassium nitrate) and 9.0 g of K2SO4...

A solid mixture consists of 51.0 g of KNO3 (potassium nitrate) and 9.0 g of K2SO4 (potassium sulfate). The mixture is added to 130. g of water. Part B If the solution described in the introduction is cooled to 0 ∘C, what mass of KNO3 should crystallize?

Solutions

Expert Solution

Solubility:

When the maximum amount of solute is dissolve in the solvent is called solubility. On the basic of solubility the solution are following types:

Saturate solution:

A solution which contains the maximum amount of dissolved solute at the equilibrium is called saturated solution.

Un-saturate solution:

A solution which contains lesser amount of solute as compare to saturated solution. It will be able to dissolver more solute.

Super -Saturate solution:

A solution which contains the more dissolved amount of solute as compare to saturated solution.

According to the problem;

There is Initially 51.0 g of KNO3 (potassium nitrate) and 9.0 g of K2SO4 (potassium sulfate). are added to 130 g of water.

These means 51.0g of KNO3 is dissolved in 130g of water.

From the other sources like solubility graph or book we know that

14 g KNO3 is soluble in 100g water at 00C

So, amount of KNO3 soluble in 130g water = 14 / 100 * 130

= 18.2 g

Here 51.0 g KNO3 present; out of which 18.2 g KNO3 is soluble

So, amount of KNO3 crystallizes 51.0 – 18.2 = 32.8 g KNO3 will get crystallized


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