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A solid mixture consists of 39.1 g of KNO3 (potassium nitrate) and 6.9 g of K2SO4...

A solid mixture consists of 39.1 g of KNO3 (potassium nitrate) and 6.9 g of K2SO4 (potassium sulfate). The mixture is added to 130. g of water.

A. Consider the mixture described in the introduction. At 60 ∘C , to what extent will each solute be dissolved? (Totally dissolved, partially dissolved, not dissolved)

B. If the solution is cooled to 0 degrees Celsius, what mass, in grams, would KNO3 crystallize?

Expert Solution

initially solid mixture has

mass of KNO3 = 39.1 g

mass of K2SO4 = 6.9 g

total mixture added to 130 g of water

from the graph , solubility of K2SO4 in water at 60oC is = (18 / 100 ) x 130

= 23.4 g K2SO4

23.4 g K2SO4 > 6.9 g of K2SO4.

so total K2SO4 is completely dissolved

from the graph , solubility of KNO3 in water at 60oC is = (50 / 100 ) x 130

= 65 g KNO3

65 g KNO3 > 39.1 g of KNO3.

so total KNO3 is completely dissolved

B)

from the graph , solubility of KNO3 in water at 0oC is = (15 / 100) x 130

= 19.5 g KNO3

we have 39.1 g KNO3 . but soluble is 19.5 g KNO3. so remaining will form crystalls

mass of KNO3 crystallized = 39.1 - 19.5 = 19.6 g KNO3

queen_honey_blossom answered 2 years ago

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