Question

A sample of an ideal gas at 1.00 atm and a volume of 1.02 L was placed in a weighted balloon and dropped into the ocean. As the sample descended, the water pressure compressed the balloon and reduced its volume. When the pressure had increased to 45.0 atm, what was the volume of the sample? Assume that the temperature was held constant.

Answer 1

We know that PV = nRT

Where

T = Temperature ;P = pressure ; n = No . of moles ;R = gas constant ; V= Volume of the gas

As the gas remains the same , n will constant also T remains the same.

So PV = constant

Thereby PV = P'V'

Where

P = initial pressure = 1.00 atm

V = initial volume = 1.02 L

P'= final pressure = 45.0 atm

V' = final volume = ?

Plug the values we get   V' = (PV) / P'

                                       = (1x1.02) / 45.0

                                       = 0.023 L

Therefore the volume of the sample is 0.023L