Question

In: Chemistry

A sample of oxygen gas occupies a volume of 9.30 L at 52.0°C and 0.790 atm....

A sample of oxygen gas occupies a volume of 9.30 L at 52.0°C and 0.790 atm. If it is desired to increase the volume of the gas sample to 11.0 L, while decreasing its pressure to 0.569 atm, the temperature of the gas sample at the new volume and pressure must be °C.

Solutions

Expert Solution

Initial                                                       Final

V1 = 9.30L                                                          V2   = 11L

P1   = 0.790atm                                                    P2 = 0.569atm

T1   = 52+273   = 325K                                        T2 =

        P1V1/T1     =       P2V2/T2

              T2        =       P2V2T1/P1V1

                          =       0.569*11*325/(0.790*9.30)

                          = 276.87K

                             = 276.87-273   = 3.870C   >>>>answer


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