A sample of oxygen gas occupies a volume of 9.30 L at 52.0°C and 0.790 atm....

A sample of oxygen gas occupies a volume of 9.30 L at 52.0°C and 0.790 atm. If it is desired to increase the volume of the gas sample to 11.0 L, while decreasing its pressure to 0.569 atm, the temperature of the gas sample at the new volume and pressure must be °C.

Expert Solution

Initial Final

V1 = 9.30L V2 = 11L

P1 = 0.790atm P2 = 0.569atm

T1 = 52+273 = 325K T2 =

P1V1/T1 = P2V2/T2

T2 = P2V2T1/P1V1

= 0.569*11*325/(0.790*9.30)

= 276.87K

= 276.87-273 = 3.87⁰C >>>>answer

queen_honey_blossom answered 1 year ago

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