A sample of an ideal gas has a volume of 3.65 L at 13.00 °C and...

A sample of an ideal gas has a volume of 3.65 L at 13.00 °C and 1.80 atm. What is the volume of the gas at 24.00 °C and 0.990 atm?

Expert Solution

Initial conditions of ags:

Pressure P1 = 1.80 atm

Volume V1 = 3.65 L

Temperature T1 = 13 ^oC = 13 + 273 K = 286 K

Final conditions of gas:

Pressure P2 = 0.990 mmHg

Volume V2 = ? L

Temperature T2 = 24 ^oC = 24 + 273 K = 297 K

We know that P1V1/T1 = P2V2/T2

V2 = (P1V1/T1) (T2/P2)

= ( 1.80 atm x 3.65 L/ 286 K ) ( 297 K/ 0.990 atm)

= 6.89 L

V2 = 6.89 L

Therefore, volume of the gas at 24.00 °C and 0.990 atm = 6.89 L

queen_honey_blossom answered 2 months ago

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