A 1.00 L sample of a gas at 25.0

Expert Solution

Number of moles of Helium, n_He = mass / molar mass

= 50.0 g / 4 gmol^-1 If we assume total sample mass is 100 g

= 12.5 mol

Number of moles of Neon , n_Ne = mass / molar mass

= 50.0 g / 20 gmol ^-1

= 2.5 mol

Total number of moles , n = n_He + n_Ne

= 12.5 + 2.5

= 15.0 mol

Mole fraction of Neon , X _Ne = n_Ne / n

= 2.5 / 15.0

= 0.167

partial pressure of Neon , p _Ne = total pressure x mole fraction of Neon

= 1.0 atm x 0.167

= 0.167 atm

queen_honey_blossom answered 2 years ago

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