In: Statistics and Probability
The expected times and variances for the project activities are given below. Complete the table showing which activities are critical.
ID | Description | Predecessor | Te | Variance | Critical? |
1 | Pilot Production | None | 6 | 3 | ? |
2 | Select Channels of Distribution | None | 20 | 4 | ? |
3 |
Develope Mktg. Program |
None | 18 | 2 | ? |
4 | Test Market | 1 | 4 | 2 | ? |
5 | Patent | 1 | 17 | 5 | ? |
6 | Full production | 4 | 9 | 10 | ? |
7 | Ad Promotion | 3 | 16 | 2 | ? |
8 | Release | 2,5,6,7 | 2 | 1 | ? |
What is the probability of completing the project in 27 periods? Hint: Use the =NORM.S.DIST(z, TRUE) function in Excel to compute the probability. (Do not round intermediate calculations. Round the final answer to 3 decimal places, i.e., 0.750.)
1). What is the probability of completing the project in 27 time periods?_____
***PLEASE SHOW ALL WORK! I AM TRYING TO LEARN :)***
Solution:
To fin Critical path and duration of project, we will create
Network diagram, forward and backward pass
From the forward and backward pass, we found that critical path is
3-7-8 with critical time (18+16+2) = 36
Critical activities are those activities which have zero slack. So
Critical activities are 3, 7 and 8
ID |
Te |
Variance |
Critical? |
1 |
6 |
3 |
No |
2 |
20 |
4 |
No |
3 |
18 |
2 |
Yes |
4 |
4 |
2 |
No |
5 |
17 |
5 |
No |
6 |
9 |
10 |
No |
7 |
16 |
2 |
Yes |
8 |
2 |
1 |
Yes |
We need to calculate probability that the project will complete
in 27 periods
Critical time = 36 periods
Variance = (2+2+1) = 5 periods
Standard deviation = sqrt(5) = 2.24
Z-score = (X-mean)/Standard deviation = (27-36)/2.24 = -4.02
From normal distribution table we found p-value
P(X<=27 periods) = 0.000029
So there is 0.003% probability of completing the project in 27
periods.