In: Statistics and Probability
Using the simple random sample of weights of women from a data set, we obtain these sample statistics: n=50 and x overbar=142.71 lb. Research from other sources suggests that the population of weights of women has a standard deviation given by sigma=31.7631.76 lb.
a. Find the best point estimate of the mean weight of all women.
b. Find a 90% confidence interval estimate of the mean weight of all women.
Solution :
Given that,
 = 142.71
 = 31.76
n = 50
(a) best point estimate of the mean = 142.71
(b)At 90% confidence level the z is ,
= 1 - 90% = 1 - 0.90 = 0.10
/ 2 = 0.10 / 2 = 0.05
Z
/2
= Z0.05 = 1.645
Margin of error = E = Z
/2* (
 /n)
= 1.645 * (31.76 / 50)
= 7.3886
At 90% confidence interval estimate of the population mean is,
 - E < 
 < 
 + E
142.71 -7.3886 < 
 < 142.71 +7.3886
135.3214< 
 < 150.0986
(135.3214 , 150.0986)