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Using the simple random sample of weights of women from a data​ set, we obtain these...

Using the simple random sample of weights of women from a data​ set, we obtain these sample​ statistics:

nequals=4040

and

x overbarxequals=147.53

lb. Research from other sources suggests that the population of weights of women has a standard deviation given by

sigmaσequals=32.57

lb.

a. Find the best point estimate of the mean weight of all women.

b. Find a 95% confidence interval estimate of the mean weight of all women.

Solutions

Expert Solution

Solution :

Given that,

point estimate of mean is = 147.53

= 147.53

= 32.57

n = 4040

At 95% confidence level the z is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

Z/2 = Z0.025 = 1.96

Margin of error = E = Z/2* ( /n)

=1.96 * (32.57 / 4040)

= 1.0043

At 95% confidence interval estimate of the population mean is,

- E < < + E

147.53 - 1.0043 < < 147.53 + 1.0043

146.5257< < 148.5343

(146.5257 ,  148.5343 )

milcah answered 1 year ago
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