In: Statistics and Probability
Using the simple random sample of weights of women from a data set, we obtain these sample statistics: the sample size is 40 and the sample mean was 151.83 pounds. Research from other sources suggests that the population of weights of women has a standard deviation of 30.43 pounds. Find the 90% confidence interval estimate of the mean weight of all women.
Solution :
Given that,
= 151.83
= 30.43
n = 40
At 90% confidence level the z is ,
= 1 - 90% = 1 - 0.90 = 0.10
/ 2 = 0.10 / 2 = 0.05
Z/2 = Z0.05 = 1.645
Margin of error = E = Z/2* ( /n)
=1.645 * (30.43 / 40)
= 7.9148
At 90% confidence interval estimate of the population mean is,
- E < < + E
151.83 - 7.9148< <151.83 + 7.9148
143.9152< < 159.7448
(143.9152,159.7448 )