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Provide the goal of the study, clearly stating the research hypothesis. Describe the study design. Describe...

Provide the goal of the study, clearly stating the research hypothesis. Describe the study design.

Describe the results noting the direction (e.g., higher or lower; increase or decrease; etc.) and difference between sample mean (M = ?; 95% CI = ?) and the population mean (µ = ?).

Report the inferential statistic used to compute the p-value (Z [ n = ?] = observed value, p < or > .05) and state if the results are significant or not.

Report and interpret the 95% CI around the difference between the two means (e.g., does the CI contain 0 or not—how do you interpret the Ho if it does or does not include 0?). Also, be sure to report and interpret the effect size (d = ?).

1. A research team happens to know that male rats administered a placebo drug will spend μ = 5 minutes per hour grooming (σ = 6). They believe that male rats administered a low dose of the street drug ecstasy will spend less than 5 minutes per hour grooming. They chose 100 male rats, administered a low dose of ecstasy to each, then measured the number of minutes per hour each rat spent grooming. The mean of this sample was M = 4. The research question the researcher want to answer is: does administering a low dose of ecstasy affect the time spent grooming?

Solutions

Expert Solution

1) H0:

    H1:

The test statistic z = ()/()

                             = (4 - 5)/(6/)

                             = -1.67

P-value = P(Z < -1.67)

             = 0.0475

Since the P-value is less than the significance level(0.0475 < 0.05), so we should reject the null hypothesis.At 0.05 significance level, there is sufficient evidence to conclude that a low does of ecstasy affect the time spent grooming.

At 95% confidence level, the critical value is z0.025 = 1.96

The 95% confidence interval is

+/- z0.025 *

= 4 +/- 1.96 * 6/

= 4 +/- 1.176

= 2.824, 5.176

Since the interval does not contain 0, so we should reject the null hypothesis.

Cohen's d =

                 = (4 - 5)/6

                 = -0.16


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