Question

1.Density water = 1 kg/m^3 and density of ice = 90% density of water. How much of an ice cube in your glass of water is below the surface? calculate the specific gravity of ice. (show work )

2. a piece of cork which weights 0.25 N in air and has a specific gravity of 0.25 . If the cork is allowed to float in water, what fraction of its volume will be above water ?

Answer 1

Specific gravity is the ratio of density of object to the density of water

   given density of water = 1 kg/m3

       density of ice = 905 of density of water = 0.9 kg/m3

How much of an ice cube in your glass of water is below the surface is

first calculating the fraction of volume of ice above the water surface is

  
   1 - vs/vo, here Vs is volume of object in water
           Vo is volume of object

and relation Vs/Vo = So/Sw; so specific gravity of object, sl - specific gravity of liquid(water)

       1- so/sw = 1-0.9/1 = 0.1

so the volume of the ice in your glass water is below the surface is 90%.

2.

specific gravity of piece of cork 0.25 and weighs in air 0.25 N

what fraction of its volume will be above water is 1-1 - vs/vo, here Vs is volume of object in water
                                   Vo is volume of object

   and relation Vs/Vo = So/Sw; so specific gravity of object, sl - specific gravity of liquid(water)

       1- so/sw = 1-0.25/1 = 0.75

0.75 part or 75% of cork volume is on the above water