Question

Problem 2 How much ice is in the final state after 2 kg of ice at -30°C is added to a large quantity of water at 0°C? The final state is ice-water. (10 points)

Answer 1

Heat gained by ice to reach a state of ice at 0 degree Celsius = m×c×∆T

= 2×2090×30

= 125400 joule

Now more heat required to convert this ice at 0 degree Celsius to water at 0 degree Celsius =

m L​​​f = 2×334000 = 668000 Joules

Therefore total heat absorbed = 125400+668000=793400 joules

Now this amount of heat will be released by large quantity of water initially at 0 degree Celsius

Therefore, on loosing this amount of energy, some of water will be converted into ice

793400 = m1 × 334000

m1= 2.37 kg

Therefore in the final mixture there will be 2.37 kg of ice and rest water .

Hence a final mixture will have a state of ice-water.

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