Question

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###############python#################

# RQ1
def merge(dict1, dict2):
    """Merges two Dictionaries. Returns a new dictionary that combines both. You may assume all keys are unique.

    >>> new =  merge({1: 'one', 3:'three', 5:'five'}, {2: 'two', 4: 'four'})
    >>> new == {1: 'one', 2: 'two', 3: 'three', 4: 'four', 5: 'five'}
    True
    """
    "*** YOUR CODE HERE ***"


# RQ2
def counter(message):
    """ Returns a dictionary where the keys are the words in the message, and each
    key is mapped (has associated value) equal 
    to the number of times the word appears in the message.
    >>> x = counter('to be or not to be')
    >>> x['to']
    2
    >>> x['be']
    2
    >>> x['not']
    1
    >>> y = counter('run forrest run')
    >>> y['run']
    2
    >>> y['forrest']
    1
    """
    "*** YOUR CODE HERE ***"

Answer 1

def merge(dict1, dict2):
"""Merges two Dictionaries. Returns a new dictionary that combines both. You may assume all keys are unique.

>>> new = merge({1: 'one', 3:'three', 5:'five'}, {2: 'two', 4: 'four'})
>>> new == {1: 'one', 2: 'two', 3: 'three', 4: 'four', 5: 'five'}
True
"""
"*** YOUR CODE HERE ***"
new={}
for i in dict1:
new[i]=dict1[i]
for i in dict2:
new[i]=dict2[i]
return new

def counter(message):
""" Returns a dictionary where the keys are the words in the message, and each
key is mapped (has associated value) equal
to the number of times the word appears in the message.
>>> x = counter('to be or not to be')
"""
words=message.split()
dict1={}
for i in words:
dict1[i]=dict1.get(i,0)+1
return dict1