no dictionaries please Returns a new string which is lowercase version of the given word with...

no dictionaries please

Returns a new string which is lowercase version of the given word
with special characters and digits removed

The returned word should not have any of the following characters:
! . ? : , ' " - _ \ ( ) [ ] { } % 0 1 2 3 4 5 6 7 8 9 tab character and new-line character

>>> clean_word("co-operate.")
'cooperate'
>>> clean_word("Anti-viral drug remdesivir has little to no effect on Covid patients' chances of survival, a study from the World Health Organization (WHO) has found.")
'antiviral drug remdesivir has little to no effect on covid patients chances of survival a study from the world health organization who has found'
>>> clean_word("1982")
''
>>> clean_word("born_y1982_m08\n")
'bornym'

Expert Solution

Here is the function, no dictionary were used


================================================================

def clean_word(sentence):
    cleaned_word = ''
    filtered = '!.?:,\'"-_\()[]{}%0123456789'
    for letter in sentence:
        if letter not in filtered:
            cleaned_word += letter
    return cleaned_word.lower()


def main():
    print(clean_word("co-operate."))
    print(clean_word(
        "Anti-viral drug remdesivir has little to no effect on Covid patients' chances of survival, a study from the World Health Organization (WHO) has found."))
    print(clean_word('1982'))
    print(clean_word("born_y1982_m08\n"))


main()

==================================================================

venereology answered 5 months ago

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