If Kc = 4.4 x 10^-2 for PCl3(g) + Cl2(g) ⇄ PCl5(g) at 520 K, what...

If Kc = 4.4 x 10^-2 for PCl3(g) + Cl2(g) ⇄ PCl5(g) at 520 K, what is the value of Kp for this reaction at this temperature? Express your answer using two significant figures.

Expert Solution

Given K_c = 4.4 x 10^-2

We know that K_p = K_c x (RT) ⁿ

Where n = change in number of moles

= number of moles of gaseous products - number of moles of gaseous reactants

PCl₃(g) + Cl₂(g) ⇄ PCl₅(g)

For the given reaction n = 1 - ( 1 + 1 ) = -1

R = gas constnat = 0.0821 L-atm / ( mol - K )

T = Temperature = 520 K

Plug the values we get K_p = K_c x (RT) ⁿ

K_p = 4.4 x 10^-2x (0.0821 x 520) ^-1

= 1.0x10^-3

Therefore K_p of this reaction is 1.0x10^-3

queen_honey_blossom answered 4 months ago

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