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For the equilibrium PCl5(g) PCl3(g) + Cl2(g), Kc = 4.0 at 228°C. If pure PCl5 is placed in a 1.00-L container and allowed to come to equilibrium, and the equilibrium concentration of PCl5(g) is 0.26 M, what is the equilibrium concentration of PCl3?

Expert Solution

PCl₅(g) <----> PCl₃(g) + Cl₂(g), Kc = 4.0

Equilibrium constant , Kc = ( [PCl₃(g) ] [ Cl₂(g)]) / [ PCl₅(g)]

( X * X ) / 0.26 = 4.0

X² = 0.26*4.0

= 1.04

X = 1.02 M

So the equilibrium concentration of PCl3 is 1.02 M

queen_honey_blossom answered 1 year ago

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