PCl5(g)--->PCl3(g)+Cl2(g) Kc= 1.80 at 250 degrees celcius A 0.173 mol sample of PCl5(g) is injected into...

PCl5(g)--->PCl3(g)+Cl2(g)

Kc= 1.80 at 250 degrees celcius

A 0.173 mol sample of PCl5(g) is injected into an empty 2.55 L reaction vessel held at 250 °C. Calculate the concentrations of PCl5(g) and PCl3(g) at equilibrium.

Solutions

Expert Solution

Ans. Initial [PCl₅] = moles / vol. of reaction vessel in liters

= 0.173 mol / 2.55 L = 0.0678 M

# Result:

Equilibrium [PCl₅] = 0.0024 M

Equilibrium [PCl₃] = 0.0654 M

queen_honey_blossom answered 1 year ago

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