In: Chemistry
PCl5(g)--->PCl3(g)+Cl2(g)
Kc= 1.80 at 250 degrees celcius
A 0.173 mol sample of PCl5(g) is injected into an empty 2.55 L
reaction vessel held at 250 °C. Calculate the concentrations of
PCl5(g) and PCl3(g) at equilibrium.
Ans. Initial [PCl5] = moles / vol. of reaction vessel in liters
= 0.173 mol / 2.55 L = 0.0678 M
# Result:
Equilibrium [PCl5] = 0.0024 M
Equilibrium [PCl3] = 0.0654 M