Question

In: Advanced Math

Solve by variation of parameters: A. y" + 6y' + 9y = e^(-3t)/(1 + t^2) B....

Solve by variation of parameters:

A. y" + 6y' + 9y = e^(-3t)/(1 + t^2)

B. y" − y = e^t − e^-t.

Solutions

Expert Solution

Question-(A)

.

for homogeneous system, find roots

for one real root, complementary solution is

.

take derivative

now find Wronskian

find determinant

and we have

.

.

now perticular solution is

.

.

general solution is

.

.

.

Question-(B)

.

for homogeneous system, find roots

for 2 real roots, complementary solution is

.

take derivative

now find Wronskian

find determinant

and we have

.

.

now perticular solution is

.

general solution is

take


Related Solutions

Solve by variation of parameters: A. y"−9y = 1/(1 − e^(3t)) B. y" +2y'+26y = e^-t/sin(5t)
Solve by variation of parameters: A. y"−9y = 1/(1 − e^(3t)) B. y" +2y'+26y = e^-t/sin(5t)
Find a particular solution to y''+6y'+9y=(-18.5e^(-3t))/(t^2+1)
Find a particular solution to y''+6y'+9y=(-18.5e^(-3t))/(t^2+1)
($4.6 Variation of Parameters): Solve the equations (a)–(c) using method of variation of parameters. (a) y''-6y+9y=8xe^3x...
($4.6 Variation of Parameters): Solve the equations (a)–(c) using method of variation of parameters. (a) y''-6y+9y=8xe^3x (b) y''-2y'+2y=e^x (secx) (c) y''-2y'+y= (e^x)/x
t^2 y'' − 4ty' + 6y = t^4*e^t , t > 0. Use variation of parameters...
t^2 y'' − 4ty' + 6y = t^4*e^t , t > 0. Use variation of parameters to find a particular solution given that y1 = t^2 and y2 = t^3 are a fundamental set of solutions to the corresponding homogeneous equation
Solve y''-y'-2y=e^t using variation of parameters.
Solve y''-y'-2y=e^t using variation of parameters.
Use variation of parameters to solve the following differential equations y''-5y'-6y=tln(t)
Use variation of parameters to solve the following differential equations y''-5y'-6y=tln(t)
Solve both ways: a) y" -2y' + y = e^2x b) Solve only by variation of parameters
  Solve both ways: a) y" -2y' + y = e^2x b) Solve only by variation of parameters b) y" -9y = x/(e^3x) c) y" -2y' + y = (e^x)/(x^4) d) y" + y = sec^3 x
Solve the laplace transform to solve the initial value problem. y"-6y'+9y=t. Y(0)=0, y'(0)=1
Solve the laplace transform to solve the initial value problem. y"-6y'+9y=t. Y(0)=0, y'(0)=1
Find the general solution of the ODE: y'' − 6y' + 9y = (1 + x^2)e^2x...
Find the general solution of the ODE: y'' − 6y' + 9y = (1 + x^2)e^2x .
Solve y^4-4y"=g(t) using variation of parameters.
Solve y^4-4y"=g(t) using variation of parameters.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT