Question
In: Advanced Math
Solve y''-y'-2y=e^t using variation of parameters.
Solve y''-y'-2y=e^t using variation of parameters.
Solutions
Colby Messinger answered 2 years agoRelated Solutions
Solve both ways: a) y" -2y' + y = e^2x b) Solve only by variation of parameters
Solve both ways:
a) y" -2y' + y = e^2x
b) Solve only by variation of parameters
b) y" -9y = x/(e^3x)
c) y" -2y' + y = (e^x)/(x^4)
d) y" + y = sec^3 x
Solve by variation of parameters: A. y"−9y = 1/(1 − e^(3t)) B. y" +2y'+26y = e^-t/sin(5t)
Solve by variation of parameters:
A. y"−9y = 1/(1 − e^(3t))
B. y" +2y'+26y = e^-t/sin(5t)
Solve : y''+2y'+y=e^-x + sinx by Undetermined Coefficients method and Variation of Parameters
Solve : y''+2y'+y=e^-x + sinx by Undetermined Coefficients
method and Variation of Parameters
Solve the following equation using the method of variation of parameters : x2 y'' − 2y...
Solve the following equation using the method of variation of
parameters :
x2 y'' − 2y = 3x2 − 1, x > 0.
use variation of parameters to solve y''+y'-2y=ln(x)
use variation of parameters to solve
y''+y'-2y=ln(x)
Solve the differential equation by variation of parameters. 2y'' + y' = 6x
Solve the differential equation by variation of parameters.
2y'' + y' = 6x
Solve y^4-4y"=g(t) using variation of parameters.
Solve y^4-4y"=g(t) using variation of parameters.
Solve by variation of parameters: A. y" + 6y' + 9y = e^(-3t)/(1 + t^2) B....
Solve by variation of parameters:
A. y" + 6y' + 9y = e^(-3t)/(1 + t^2)
B. y" − y = e^t − e^-t.
Find the general solution y(t) to the following ODE using ONLY the Variation of Parameters: y"+4y'-2y...
Find the general solution y(t) to the following ODE using ONLY
the Variation of Parameters:
y"+4y'-2y = 2x2-3x+6
Solve using variation of parameters. y′′ + y = sec2(x)
Solve using variation of parameters.
y′′ + y = sec2(x)
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