Find the general solution to the differential equation below.
y′′ − 6y′ + 9y = 24t−5e3
Calculate the inverse Laplace transform of ((3s-2)
e^(-5s))/(s^2+4s+53)
Calculate the Laplace transform of y = cosh(at) using the
integral definition of the Laplace transform. Be sure to note any
restrictionson the domain of s. Recall that cosh(t)
=(e^t+e^(-t))/2
Find the general solution of the differential equation
y′′+9y=13sec2(3t), 0<t<π/6.
Use C1, C2,... for the constants of integration. Enter an exact
answer. Enter ln|a| as ln(|a|), and do not simplify.
y(t)=