Question

In: Advanced Math

Solve by variation of parameters: A. y"−9y = 1/(1 − e^(3t)) B. y" +2y'+26y = e^-t/sin(5t)

Solve by variation of parameters:

A. y"−9y = 1/(1 − e^(3t))


B. y" +2y'+26y = e^-t/sin(5t)

Solutions

Expert Solution

Colby Messinger answered 1 week ago
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