Question

Use c++ programming Construct an array of 1000 random integers within range [0, 100] An input file input.txt is provide. Each line of input.txt is a query integer that you need to check how many of that number is in your random integer array. For each query integer, fork a new child process to do the counting. The output is for each input query, output the count and child process id. For example: $> query: 13 count: 5 pid: 13342 $> query: 22 count: 3 pid: 13357 Here is the input.txt 5 13 24 6 17 20 1 51 36 42 2 19 67 35 64 91 96 84 72

Use c++ programming

Answer 1

Solution:

first make a text file with name "input.txt" and write the content to the file:

10
20
30
40
50
60

Make sure each number is in one line and file is accessible to the program.

Now, run the following program,

#include <iostream>

#include <unistd.h>

#include <sys/wait.h>

#include <string.h>

#include <stdlib.h>

#include <time.h>

#include<stdio.h>

using namespace std;

int main(int argc, char *argv[])

{

int arr[1000];

int number;

char line[10];

pid_t pid;

FILE *f = fopen("input.txt", "r"); //opening file

//generating numbers

srand(time(0)); //seed to random number generator

for(int i = 0; i<1000; i++)

arr[i] = rand() % 101;

cout<<endl;

while( fgets(line, 10, f) )

{

sscanf(line, "%d", &number); //reading the number

pid = fork();

if ( pid == 0 )

{

int count = 0, index = 0;

while( index<1000 )

{

if( arr[index] == number )

count++;

index++;

}

cout<<"query: "<<number<<"\tcount: "<<count<<"\tpid: "<<getpid()<<endl;

fclose(f);

exit(1);

}

else

{

wait(NULL);

}

}

cout<<endl;

return 0;

}

Output:

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