Question

Construct an array of 1000 random integers within range [0, 100]

An input file input.txt is provide. Each line of input.txt is a query integer that you need to check how many of that number is in your random integer array. For each query integer, fork a new child process to do the counting. The output is for each input query, output the count and child process id. For example:

$> query: 13    count: 5    pid: 13342

$> query: 22    count: 3    pid: 13357

5
13
24
6
17
20
1
51
36
42
2
19
67
35
64
91
96
84
72

Answer 1

PLEASE GIVE IT A THUMBS UP, I SERIOUSLY NEED ONE, IF YOU NEED ANY MODIFICATION THEN LET ME KNOW, I WILL DO IT FOR YOU

SINCE IT IS USING RANDOM VALUE THAT'S WHY OUTPUT DIFFER

#include <iostream>

#include <unistd.h>

#include <sys/wait.h>

#include <string.h>

#include <stdlib.h>

#include <time.h>

#include <stdio.h>

using namespace std;

int main(int argc, char *argv[])

{

  int arr[1000];

  int number;

  char line[10];

  pid_t pid;

  FILE *f = fopen("input.txt", "r"); //opening file

  //generating numbers

  srand(time(0)); //seed to random number generator

  for (int i = 0; i < 1000; i++)

    arr[i] = rand() % 101;

  cout << endl;

  while (fgets(line, 10, f))

  {

    sscanf(line, "%d", &number); //reading the number

    pid = fork();

    if (pid == 0)

    {

      int count = 0, index = 0;

      while (index < 1000)

      {

        if (arr[index] == number)

          count++;

        index++;
      }

      cout << "query: " << number << "\tcount: " << count << "\tpid: " << getpid() << endl;

      fclose(f);

      exit(1);
    }

    else

    {

      wait(NULL);
    }
  }

  cout << endl;

  return 0;
}

input.txt

5
13
24
6
17
20
1
51
36
42
2
19
67
35
64
91
96
84
72