Question

In: Chemistry

1. Using average atomic masses calculate the number of atoms present in each of the following...

1. Using average atomic masses calculate the number of atoms present in each of the following samples.

(a) 1.27 g of silver, Ag

(b) 0.0010 mol of copper, Cu

(c) 0.0010 g of copper, Cu

(d) 1.76 kg of magnesium, Mg

(e) 2.45 oz of calcium, Ca

(f) 2.45 g of calcium, Ca

(g) 2.45 mol of calcium, Ca

Solutions

Expert Solution

Remember:

Number of atoms = avogadro's number * number of moles
                                  = (6.022*10^23) *mass/molar mass
(a) 1.27 g of silver, Ag
mass= 1.27 gm
molar mass = 108 gm
number of atoms = (6.022*10^23) *mass/molar mass
                                      = (6.022*10^23) *1.27/108
                                      = 7.08*10^21 atoms

(b) 0.0010 mol of copper, Cu
Number of atoms = avogadro's number * number of moles
                                  = (6.022*10^23) * 0.001
                                 = 6.022*10^20 atoms
(c) 0.0010 g of copper, Cu
mass= 0.0010 gm
molar mass = 63.5 gm
number of atoms = (6.022*10^23) *mass/molar mass
                                      = (6.022*10^23) *0.0010/ 63.5
                                      = 9.48*10^18 atoms
(d) 1.76 kg of magnesium, Mg
mass= 1.76 Kg = 1760 gm
molar mass = 24.3 gm
number of atoms = (6.022*10^23) *mass/molar mass
                                      = (6.022*10^23) *1760/ 24.3
                                      = 4.36*10^25 atoms
(e) 2.45 oz of calcium, Ca
1 Oz= 28.35 gm
mass= 2.45 oz = 2.45*28.35 gm = 69.46 gm
molar mass = 40 gm
number of atoms = (6.022*10^23) *mass/molar mass
                                      = (6.022*10^23) *69.46/ 40
                                      = 1.0*10^24 atoms
(f) 2.45 g of calcium, Ca
mass= 2.45 gm
molar mass = 40 gm
number of atoms = (6.022*10^23) *mass/molar mass
                                      = (6.022*10^23) *2.45/ 40
                                      = 3.69*10^22 atoms
(g) 2.45 mol of calcium, Ca
Number of atoms = avogadro's number * number of moles
                                  = (6.022*10^23) * 2.45
                                 = 1.48*10^24 atoms


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