Question

In: Chemistry

Use average atomic masses to calculate the number of moles of the element present in each...

Use average atomic masses to calculate the number of moles of the element present in each of the following samples.

(a) 66.76 g of fluorine atoms


(b) 405.0 mg of mercury

(c) 84.04 g of silicon

(d) 48.65 g of platinum

(e) 2426 g of magnesium

(f) 47.77 g of molybdenum

Solutions

Expert Solution

(a) 66.76 g of fluorine atoms
mass= 66.76 gm
molar mass of F = 19 gm
number of moles of fluorine atoms = mass /molar mass
                                                                               = 66.76/19
                                                                                 = 3.5 mol
(b) 405.0 mg of mercury
mass= 405 mg = 0.405 gm
molar mass of mercury = 200.5 gm
number of moles of mercury = mass /molar mass
                                                                               = 0.405/200.5
                                                                                 = 2.02*10^-3 mol
                                                                                 = 2.02 mmol
(c) 84.04 g of silicon
mass= 84.04 g
molar mass of silicon= 28 gm
number of moles of silicon= mass /molar mass
                                                                               = 84.04/28
                                                                                 = 3 mol
(d) 48.65 g of platinum
mass= 48.65 g
molar mass of platinum= 195 gm
number of moles of platinum= mass /molar mass
                                                                               = 48.65 /195
                                                                                 = 0.25 mol
(e) 2426 g of magnesium
mass= 2426 g
molar mass of magnesium= 24 gm
number of moles of magnesium= mass /molar mass
                                                                               = 2426 /24
                                                                                 = 101.1 mol
(f) 47.77 g of molybdenum
mass= 47.77 g
molar mass of molybdenum= 96 gm
number of moles of molybdenum= mass /molar mass
                                                                               = 47.77 /96
                                                                                 = 0.5 mol


Related Solutions

Name the element with atomic number (Z) = 15 and atomic mass number = 31, Use...
Name the element with atomic number (Z) = 15 and atomic mass number = 31, Use the symbol, not the word. How many electrons does the neutral atom of this element have? Use a number, not a word. How many neutrons does the neutral atom of this element have? Use a number, not a word.
Calculate the number of moles of solute present in each of the following aqueous solutions. 600...
Calculate the number of moles of solute present in each of the following aqueous solutions. 600 mL of 0.250 M SrBr2 122.0 g of a solution that is 6.65% glucose (C6H12O6) by mass.
If an element has an atomic number of 7 and an atomic mass number of 15,...
If an element has an atomic number of 7 and an atomic mass number of 15, how many protons, neutrons, and electrons does it possess? a) 7 protons, 8 neutrons, and 7 electrons b) 7 protons, 8 neutrons, and 8 electrons c) 8 protons, 7 neutrons, and 8 electrons d) 15 protons, 8 neutrons, and 8 electrons
An element has an atomic number of 76. The number of protons and electrons in a...
An element has an atomic number of 76. The number of protons and electrons in a neutral atom of the element are?
A hypothetical element Ec has an atomic number of 156 and an atomic mass of 300....
A hypothetical element Ec has an atomic number of 156 and an atomic mass of 300. 1. How many neutrons and electrons would be found in a neutral Ec atom? 2. If one proton were removed from Ec, would it still be the same element? 3. If one electron were to be gained by an atom of Ec, would it still be the same element? Would anything change about the element?
Each element has a unique atomic number, which is listed on the periodic table above the...
Each element has a unique atomic number, which is listed on the periodic table above the chemical symbol for the element. The atomic number is equal to the charge on the nucleus. The atomic number also equals the number of protons in the nucleus and the number of electrons in the neutral atom of the element. For example, Fluorine (F) has the atomic number 9, which means that its atoms contain 9 protons and 9 electrons. Zinc (Zn) has the...
1.Calculate the number of moles of solute present in am aqueous solution of 86.3 g of...
1.Calculate the number of moles of solute present in am aqueous solution of 86.3 g of 0.160 m KCl. 2. The density of toluene (C7H8) is 0.867g/mL, and the density of thiophene (C4H4S) is 1.065 g/mL. A solution is made by dissolving 9.38g of thiophene in 270 mL of toluene. Calculate the (a) percentage and (b) Molality of thiophene.
Element “X” has an atomic number of 16 and an atomic mass of 40 How many...
Element “X” has an atomic number of 16 and an atomic mass of 40 How many electrons are in the valence of Element X?
Determine the number of moles of the compound and determine the number of moles of each...
Determine the number of moles of the compound and determine the number of moles of each type of atom in each of the following: (a) 2.12 g of potassium bromide, KBr (b) 0.1488 g of phosphoric acid, H3PO4 (c) 23 kg of calcium carbonate, CaCO3 (d) 78.452 g of aluminum sulfate, Al2(SO4)3 (e) 0.1250 mg of caffeine, C8H10N4O2
calculate the number of atoms in 100.0g of mercury: Part 3: Average Mass: Atomic Mass =...
calculate the number of atoms in 100.0g of mercury: Part 3: Average Mass: Atomic Mass = (0.1687 X 198.968254) + (0.2310 X 199.968300) + (0.1318 X 200.970277) + (0.2986 X 201.970617) = 166.35 amu Isotope: 199Hg, 198.968254 amu, 16.87 % abundance Isotope: 200Hg, 199.968300 amu, 23.10 % abundance Isotope: 201Hg, 200.970277 amu, 13.18 % abundance Isotope: 202Hg, 201.970617 amu, 29.86 % abundance Part 4: Use the average mass calculated in Part 3 to calculate the number of atoms in 100.0g...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT