Question

Calculate each of the following.

Part A

number of Ag atoms in 0.125 mole of Ag

Part B

number of C3H8O molecules in 0.925 mole of C3H8O

Part C

number of Cr atoms in 7.00 moles of Cr

Answer 1

Part A

number of Ag atoms in 0.125 mole of Ag

1 mol contain -------------- 6.023 x 10^23 atoms

0.125 mol Ag --------------- ?? atoms

number of Ag atoms = 0.125 x 6.023 x 10^23

                                  = 7.529 x 10^22 atoms

Part B

number of C3H8O molecules in 0.925 mole of C3H8O

number of C3H8O molecules = 0.925 x 6.023 x 10^23

                                                = 5.571 x 10^23 molecules

Part C

number of Cr atoms in 7.00 moles of Cr

number of Cr atoms = 7.00 x 6.023 x 10^23

                                = 4.216 x 10^24 atoms