Question

Calculate the number of moles of solute present in each of the following aqueous solutions. 600 mL of 0.250 M SrBr2 122.0 g of a solution that is 6.65% glucose (C6H12O6) by mass.

Answer 1

Solution :-

Calculating moles of SrBr2 in 600 ml of 0.250 M solution :-

Moles = molarity * volume in liter

            = 0.250 mol per L * 0.600 L

           = 0.150 mol SrBr2

So it contains 0.150 mol SrBr2

Now lets calculate moles in the 6.65 % glucose (C6H12O6) solution.

Lets assume we have 100 ml solution

Then mass of glucose present = 6.65 g

Calculating moles of 6.65 g glucose

Moles of glucose = mass / molar mass

                                 = 6.65 g / 180.15 g per mol

                                 = 0.0370 mol glucose

So it contains 0.0370 moles of glucose (C6H12O6)