Question

Would stirring a cup of tea show any sign of a two dimensional vector? This is my own question I am asking. My personal question.

Answer 1

it is understood that by tea you mean the particles of tea . while you stir the tea solution in liquid state ,the particles would move in different paths ,which are quite random and weird . we can assume that the particles move in two dimensional circular paths ( but actually their motion is quite weird ) . It is quite obvious that ,one could not assign a single vector to a body executing it's motion in a circular path . You could assign infinitely many vectors to a particle moving in a circular path ( this is because a circle has infinite points on it ,and corresponding to each point you could assign a unique vector .)

If one consider the motion of particles as random , even then there is no unique vector describing the motion of the particle .

Their motion is quite random ,that one could not assign a unique vector for the motion of the particles .

For your intuition , consider the motion ( thermal agitation ) i.e, the  thermal motion of free electrons inside a piece of a conductor ( not subjected to external fields ) , can you assign a single two dimensional vector to the motion of a free electron?

of course no , because their motion is quite random ,same is in the case of tea particles .

This is my point of argument .