Question

Develop a Java program for the question below:

A running race among animals:

In a race among animals different types of animals are differenciated wih their running styles. In each iteration of the race, each participating animal makes a move acording to its style of running. Total length of the racecourt is NTotal (store this variable properly in the test class). Determine the winner animal and completion time of the race using polymorphism. Each of these animal classes extends from Animal class having a move method with no arguments. The current position of an animal is an integer atatring value is 0. In addition, each animal has a name attribute as well.

For generating random variables create an object from the Random class and invoke its randomize method with an integer argument (n).which returns an integer random number between 0 and (n-1).

• Animal class: have a move method implemented differently for each animal. It also has other instance variable(s) or method(s) required by the program.
• Rabbit class: Rabbits move as follows: with 0.4 probability a rabit sleaps makede no movment its current position in the race does not change, and with 0.6 probability make a three units move forwards. (its position increases by three units)

Note you can generate 0.4 and 0,6 proababilities with the randomize method. Invoke the method with an argument of 5 if 0 or 1 comes the rabit sleapes at this iteration, if 2,3 or 4 comes, the rabit makes a move.

• Turtle class: turtles always moves only one unit forward. Their positions increased by one unit.
• Test class: Create an array of animals. There can be more than one rabit or turlle in the race. At each iteration of the race (each time), all animals in the array makes a move in the order indicated by the indices in the array. Position of the animal is updated by the move method. Initially all positions are zero. At the end of each iteration or time, check whether one or more animals completed the race. The winner is the animal whose position exceeding the racecourts length, Ifd more than one animals’ position exceeds the racecscourts leength first during an iteration. This is a simple way of determining the winner, not the best way. Print the name, and score (in how many interations it completes the race) of the winner. Do not pay attension to the case of more then one winner (two ro more animals with same score exceeding the racecourt length at the same iteration)

Answer 1

import java.util.Random;

class Animal {

    String name;
    int position, score;

    public Animal(String name) {
        this.name = name;
        this.position = 0;
        this.score = 0;
    }

    void move() {
        this.score++;
    }
}

class Rabbit extends Animal {

    public Rabbit(String name) {
        super(name);
    }

    @Override
    void move() {
        Random random = new Random();
        if (random.nextInt(5) < 2) {
            this.position += 3;
        }
        super.move();
    }
}

class Turtle extends Animal {

    public Turtle(String name) {
        super(name);
    }

    @Override
    void move() {
        this.position += 1;
        super.move();
    }
}

class Test {

    public static void main(String[] args) {
        int NTotal = 3;
        Animal[] animals = new Animal[4];
        animals[0] = new Rabbit("harry");
        animals[1] = new Rabbit("jason");
        animals[2] = new Turtle("alpha");
        animals[3] = new Turtle("thor");
        loop:
        while (true) {
            for (int i = 0; i < animals.length; i++) {
                animals[i].move();
                if (animals[i].position > NTotal) {
                    System.out.println("Winner is " + animals[i].name + " with score " + animals[i].score);
                    break loop;
                }
            }
        }
    }

}