Question

(1 point) A random sample of 100100 observations from a population with standard deviation 19.788150778587319.7881507785873 yielded a sample mean of 93.893.8.
(a)    Given that the null hypothesis is ?=90μ=90 and the alternative hypothesis is ?>90μ>90 using ?=.05α=.05, find the following:

(i)    critical z/t score    

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Equation Editor

(ii)    test statistic ==

(b)    Given that the null hypothesis is ?=90μ=90 and the alternative hypothesis is ?≠90μ≠90 using ?=.05α=.05, find the following:

(i)    the positive critical z/t score    

(ii)    the negative critical z/t score    

(iii)    test statistic ==

The conclusion from part (a) is:

A. There is insufficient evidence to reject the null hypothesis
B. Reject the null hypothesis
C. None of the above

The conclusion from part (b) is:

A. Reject the null hypothesis
B. There is insufficient evidence to reject the null hypothesis
C. None of the above

Answer 1

(a)

(i)    critical t score = 1.66

(ii)    test statistic = 1.92

The conclusion from part (a) is:

B. Reject the null hypothesis

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(b)

(i)    critical t score = -1.984 and +1.984

(ii)    test statistic = 1.92

The conclusion from part (a) is:

B. There is insufficient evidence to reject the null hypothesis