In: Math
(1 point) A random sample of 100100 observations from a population with standard deviation 13.8313.83 yielded a sample mean of 92.392.3.
1. Given that the null hypothesis is μ=90μ=90 and the
alternative hypothesis is μ>90μ>90 using α=.05α=.05, find the
following:
(a) Test statistic ==
(b) P - value:
(c) The conclusion for this test is:
A. Reject the null hypothesis
B. There is insufficient evidence to reject the
null hypothesis
C. None of the above
2. Given that the null hypothesis is μ=90μ=90 and the
alternative hypothesis is μ≠90μ≠90 using α=.05α=.05, find the
following:
(a) Test statistic ==
(b) P - value:
(c) The conclusion for this test is:
A. Reject the null hypothesis
B. There is insufficient evidence to reject the
null hypothesis
C. None of the above
1)
H0: = 90 , Ha: > 90
a)
Test statistics
z = - / / sqrt(n)
= 92.3 - 90 / 13.83 / sqrt(100)
= 1.66
b)
p-value = P (Z > z)
= P (Z > 1.66)
= 0.0485
c)
Since p-value < 0.05 level, we have sufficient evidence to reject H0.
Reject the null hypothesis.
2)
H0: = 90 , Ha: 90
a)
Test statistics
z = - / / sqrt(n)
= 92.3 - 90 / 13.83 / sqrt(100)
= 1.66
b)
p-value = 2 * P (Z > z)
=2 * P (Z > 1.66)
= 0.097
c)
Since p-value > 0.05 level we do not have sufficient evidence to reject H0>
There is insufficient evidence to reject null hypothesis
Test statistics
z = - / / sqrt(n)
= 92.3 - 90 / 13.83 / sqrt(100)
= 1.66
b)
p-value = P (Z > z)
= P (Z > 1.66)
= 0.0485