Question
In: Statistics and Probability
A random sample of 100 observations from a population with standard deviation 17.83 yielded a sample...
A random sample of 100 observations from a population with standard deviation 17.83 yielded a sample mean of 93.
1. Given that the null hypothesis is ?=90 and the alternative hypothesis is ?>90 using ?=.05, find the following: (a) Test statistic = (b) P - value: (c) The conclusion for this test is: A. There is insufficient evidence to reject the null hypothesis B. Reject the null hypothesis C. None of the above
2. Given that the null hypothesis is ?=90 and the alternative hypothesis is ?≠90 using ?=.05, find the following: (a) Test statistic = (b) P - value: (c) The conclusion for this test is: A. Reject the null hypothesis B. There is insufficient evidence to reject the null hypothesis C. None of the above
Solutions
orchestra answered 2 years agoRelated Solutions
a random sample of 100 observations from a population. with standard deviation 60 yielded a sample...
a random sample of 100 observations from a population. with
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a random sample of 100 observations from a population. with standard deviation 60 yielded a sample...
a random sample of 100 observations from a population. with
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null hypothesis that m = 100 and the alternative hypothesis m >
100 using alpha = .05 and interpret the results b. test the null
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alpha = .05 and interpret the results c. compare the p values of
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A. There is insufficient evidence to reject the
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A random sample of 100 observations from a population with standard deviation 22.99 yielded a sample...
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(1 point) A random sample of 100100 observations from a population with standard deviation 19.788150778587319.7881507785873 yielded...
(1 point) A random sample of 100100 observations from a
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(a) Given that the null hypothesis is
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?=.05α=.05, find the following:
(i) critical z/t
score
equation editor
Equation Editor
(ii) test statistic ==
(b) Given that the null hypothesis is
?=90μ=90 and the alternative hypothesis is ?≠90μ≠90 using
?=.05α=.05, find the following:
(i) the positive critical z/t
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(ii) the negative critical z/t
score
(iii) test statistic ==...
(1 point) A random sample of 100100 observations from a population with standard deviation 13.8313.83 yielded...
(1 point) A random sample of 100100 observations from a
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alternative hypothesis is μ>90μ>90 using α=.05α=.05, find the
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(c) n = 4
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In a random sample of 100 measurements from a population with known standard deviation 200, the...
In a random sample of 100 measurements from a population with
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confidence interval for the true mean is
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