Find the concentration of Fe+3 and NCS- in the following vials: Vial # .002 M Fe(NO3)3...

Find the concentration of Fe⁺³ and NCS^- in the following vials:

Vial # .002 M Fe(NO₃)₃ .002 M KSCN Distiled Water

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1 3 mL 1 mL 6 mL

2 3 mL 2 mL 5 mL

3 3 mL 3 mL 4 mL

Expert Solution

1)
Concentration of Fe+3 = Concentration of Fe(NO3)3 * volume of Fe(NO3)3 / total volume
                                          = 0.02 * 3 /(3+1+6)
                                          = 0.006 M
Concentration of NCS- = Concentration of KSCN * volume of KSCN/ total volume
                                          = 0.02 * 1 /(3+1+6)
                                          = 0.002 M
2)
Concentration of Fe+3 = Concentration of Fe(NO3)3 * volume of Fe(NO3)3 / total volume
                                          = 0.02 * 3 /(3+2+5)
                                          = 0.006 M
Concentration of NCS- = Concentration of KSCN * volume of KSCN/ total volume
                                          = 0.02 * 2/(3+2+5)
                                          = 0.004 M
3)
Concentration of Fe+3 = Concentration of Fe(NO3)3 * volume of Fe(NO3)3 / total volume
                                          = 0.02 * 3 /(3+3+4)
                                          = 0.006 M
Concentration of NCS- = Concentration of KSCN * volume of KSCN/ total volume
                                          = 0.02 * 3 /(3+3+4)
                                          = 0.006 M

queen_honey_blossom answered 1 hour ago

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