In: Statistics and Probability
Management of a soft-drink bottling company wants to develop a method for allocating delivery costs to customers. Although one cost clearly relates to travel time within a particular route, another cost variable reflects the time required to unload the cases of soft drink at the delivery point. A sample of 20 deliveries within a territory was selected. The delivery times (in minutes) and the number of cases delivered were recorded in the file below.
|
Customer |
Number of cases |
Delivery Time |
|
1 |
52 |
32.1 |
|
2 |
64 |
34.8 |
|
3 |
73 |
36.2 |
|
4 |
85 |
37.8 |
|
5 |
95 |
37.8 |
|
6 |
103 |
39.7 |
|
7 |
116 |
38.5 |
|
8 |
121 |
41.9 |
|
9 |
143 |
44.2 |
|
10 |
157 |
47.1 |
|
11 |
161 |
43 |
|
12 |
184 |
49.4 |
|
13 |
202 |
57.2 |
|
14 |
218 |
56.8 |
|
15 |
243 |
60.6 |
|
16 |
254 |
61.2 |
|
17 |
267 |
58.2 |
|
18 |
275 |
63.1 |
|
19 |
287 |
65.6 |
|
20 |
298 |
67.3 |
a. Use the least squares method to compute the regression coefficients b0 and b1
b. Interpret the meaning of b0 and b1 in this problem
a.
| Line of Regression Y on X i.e Y = bo + b1 X | ||||
| X | Y | (Xi - Mean)^2 | (Yi - Mean)^2 | (Xi-Mean)*(Yi-Mean) |
| 52 | 32.1 | 13900.41 | 273.076 | 1948.298 |
| 64 | 34.8 | 11214.81 | 191.131 | 1464.068 |
| 73 | 36.2 | 9389.61 | 154.381 | 1203.983 |
| 85 | 37.8 | 7208.01 | 117.181 | 919.043 |
| 95 | 37.8 | 5610.01 | 117.181 | 810.793 |
| 103 | 39.7 | 4475.61 | 79.656 | 597.083 |
| 116 | 38.5 | 2905.21 | 102.516 | 545.738 |
| 121 | 41.9 | 2391.21 | 45.226 | 328.853 |
| 143 | 44.2 | 723.61 | 19.581 | 119.033 |
| 157 | 47.1 | 166.41 | 2.326 | 19.673 |
| 161 | 43 | 79.21 | 31.641 | 50.063 |
| 184 | 49.4 | 198.81 | 0.601 | 10.928 |
| 202 | 57.2 | 1030.41 | 73.531 | 275.258 |
| 218 | 56.8 | 2313.61 | 66.831 | 393.218 |
| 243 | 60.6 | 5343.61 | 143.401 | 875.373 |
| 254 | 61.2 | 7072.81 | 158.131 | 1057.558 |
| 267 | 58.2 | 9428.41 | 91.681 | 929.733 |
| 275 | 63.1 | 11046.01 | 209.526 | 1521.323 |
| 287 | 65.6 | 13712.41 | 288.151 | 1987.773 |
| 298 | 67.3 | 16409.61 | 348.756 | 2392.268 |
calculation procedure for regression
mean of X = ∑ X / n = 169.9
mean of Y = ∑ Y / n = 48.625
∑ (Xi - Mean)^2 = 124619.8
∑ (Yi - Mean)^2 = 2514.51
∑ (Xi-Mean)*(Yi-Mean) = 17450.06
b1 = ∑ (Xi-Mean)*(Yi-Mean) / ∑ (Xi - Mean)^2
= 17450.06 / 124619.8
= 0.14
bo = ∑ Y / n - b1 * ∑ X / n
bo = 48.625 - 0.14*169.9 = 24.835
value of regression equation is, Y = bo + b1 X
Y'=24.835+0.14* X
bo = 24.835
b1= 0.14
b.
value of regression equation is, Y = bo + b1 X
the regression equation is compared to line equation y = mx
+c
here, m is slope of the equation
c is the constant
so that, bo = constant = 24.835 = y intercept
b1 =slope of the equation = 0.14
X intercept = -24.835/0.14 =-177.392