In: Statistics and Probability
A soft drink bottling company just ran a long line of 12-ounce
soft drink cans filled with cola. A sample of 32 cans is selected
by inspectors looking for non-conforming items. Among the things
the inspectors look for are paint defects on the can, improper
seal, incorrect volume, leaking contents, incorrect mixture of
carbonation and syrup in the soft drink, and out-of-spec syrup
mixture. The results of this inspection are given here. Construct a
c chart from the data.
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Choose the correct c chart.
A | |
B | |
C | |
D |
Answer
Let c be the non-conformances in each of the 32 cans
Let c follow a Poisson Variable with parameter
Therefore, Mean of c, E(c) = and Standard Deviation = ^0.5
The following is the table -
Can Number |
Number of non-conformances(c) |
1 |
2 |
2 |
1 |
3 |
1 |
4 |
0 |
5 |
2 |
6 |
1 |
7 |
2 |
8 |
0 |
9 |
1 |
10 |
3 |
11 |
1 |
12 |
4 |
13 |
2 |
14 |
1 |
15 |
0 |
16 |
1 |
17 |
3 |
18 |
1 |
19 |
2 |
20 |
0 |
21 |
0 |
22 |
1 |
23 |
4 |
24 |
0 |
25 |
2 |
26 |
1 |
27 |
1 |
28 |
3 |
29 |
0 |
30 |
1 |
31 |
2 |
32 |
0 |
Total |
43 |
Size of the Sample, n = 32
In this case, the parameter is not specified. So, an appropriate estimate of is (mean of non-conformances)
Mean of the non-conformances, = 43/32 = 1.3437
The c - chart is given as -
Lower Control Limit (L.C.L.) = - 3(^0.5) = 1.3437 - 3(1.3437^0.5) = -2.1338
Since, c cannot be negative, L.C.L. is taken to be 0.
Hence,
L.C.L. = 0
Central Line = = 1.3437
Upper Control Limit (U.C.L.) = + 3(^0.5) = 1.3437 + 3(1.3437^0.5) = 4.8212
(Note that: Here, I considered the 3 limits)
A graph of the above data is given below -
(where the vertical axis represents the number of non - conformances in a can and horizontal axis represents the can number)