In: Physics
1. When an RL circuit is connected to a battery, what happens to the potential difference across the inductor?
| It is constant. | 
| It is initially at its maximum value and then decreases exponentially with time. | 
| It is initially at its maximum value and then decreases linearly with time. | 
| It is initially 0 and then increases. | 
2. If we decrease the resistance in an RL circuit, what happens to the time required for the current to reach, say, 50% of its final value after the battery is connected?
| The time is increased. | 
| The time is decreased. | 
| The time is the same. | 
3. In the two-coil setup in this section, if the current in coil 1 is increasing at a constant rate, which is true?
| The induced emf in coil 2 is increasing. | 
| The induced emf in coil 2 is decreasing. | 
| The induced emf in coil 2 is constant. | 
4. In the two-coil setup in this section, if the current in coil 1 is decreasing at a constant rate, which is true?
| The induced emf in coil 2 is constant. | 
| The induced emf in coil 2 is increasing. | 
| The induced emf in coil 2 is decreasing. | 
1. Voltage across inductor is at its maximum value and then decreases exponentially with time. As we know that the expression of voltage across inductor can be given as :-
; where v(t) is the voltage across inductor and V is source voltage
and T is time constant. As the expression is exponential and
decreases with time, so the second option is correct.
2. The equation for the time to 50 % of the final value is given as :-
;
where t is the time for current to reach 50% of final value.
Clearly, when the value of R is decreased time for the current to reach 50% of final value will increase.
3. The induced emf for the second coil can be given in terms of mutual inductance as follows :-
e = -M21 (dI1/dt); where M21 is the mutual inductance
Here, rate of change of current in coil 1 is constant, so induced emf will also be constant. Hence, option 3 is true.
4. As per question number 3, same will be case as current is decreasing only, but rate is constant. So the enduced emf will be constant, but with reversed polarity compared to 3 case. Hence, option 1 is correct.