In: Physics

A battery of EMF 10 V and internal resistance 3 Ω is connected to a resistor. If the current in the circuit is 0.5 A, what is the resistance of the resistor? What is the terminal voltage of the battery when the circuit is closed?

Given:

The EMF of the battery (E = 10 V)

The internal resistance of the battery (R = 3 Ω)

The current in the circuit (I = 0.5 A)

Consider the resistance of the resistor to be R.

The current in the circuit can be found out using Ohm’s Law as,

Rewriting the above equation, we get

Therefore,

Consider the Terminal voltage of the resistor to be V.

Then, according to Ohm’s law,

Substituting values in the equation, we get

Therefore, the resistance of the resistor is 17 Ω and the terminal voltage is 8.5 V.

The resistance of the resistor is 17 Ω and the terminal voltage is 8.5 V.

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