Question

In: Statistics and Probability

How much time do you spend talking on your phone per day? I would like you...

How much time do you spend talking on your phone per day? I would like you to guess the number of minutes. This is your null hypothesis. I then want you to secure the data from your phone for the past month and conduct a one sample hypothesis test of the mean length of your phone calls per day.   Be sure to show all your work by using excel and include your data set. Use a significance level of 0.05. You will have 30 data values showing the total of minutes you spend per day. (The easiest way to secure this data is to look at your "Recent" calls on your phone and list the total number of minutes that you have spent on the phone each day in the last 30 days. This will be the data that you will use.)

The number of minuets guessed spent on the phone each day is 25 mins.

The minutes for each day spent on the phone for the past month are: 22, 15, 34, 58, 20, 15, 0, 0, 27, 63, 13, 22, 31, 23, 19, 15, 38, 57, 0, 9, 21, 61, 26, 28, 12, 24, 17, 27, 55, 16

Solutions

Expert Solution

How much time do you spend talking on your phone per day? I would like you to guess the number of minutes. This is your null hypothesis. I then want you to secure the data from your phone for the past month and conduct a one sample hypothesis test of the mean length of your phone calls per day.   Be sure to show all your work by using excel and include your data set. Use a significance level of 0.05. You will have 30 data values showing the total of minutes you spend per day. (The easiest way to secure this data is to look at your "Recent" calls on your phone and list the total number of minutes that you have spent on the phone each day in the last 30 days. This will be the data that you will use.)

The number of minuets guessed spent on the phone each day is 25 mins.

The minutes for each day spent on the phone for the past month are: 22, 15, 34, 58, 20, 15, 0, 0, 27, 63, 13, 22, 31, 23, 19, 15, 38, 57, 0, 9, 21, 61, 26, 28, 12, 24, 17, 27, 55, 16

calculated t=0.1862

Table value of t with 29 DF at 0.05 level =2.0452

Rejection Region: Reject Ho if t < -2.0452 or t > 2.0452

Calculated t = 0.1862 , not in the rejection region

The null hypothesis is not rejected.

There is not enough evidence to reject the guess.

t Test for Hypothesis of the Mean

Data

Null Hypothesis                m=

25

Level of Significance

0.05

Sample Size

30

Sample Mean

25.6

Sample Standard Deviation

17.6510

Intermediate Calculations

Standard Error of the Mean

3.2226

Degrees of Freedom

29

t Test Statistic

0.1862

Two-Tail Test

Lower Critical Value

-2.0452

Upper Critical Value

2.0452

p-Value

0.8536

Do not reject the null hypothesis

t Test for Hypothesis of the Mean

Data

Null Hypothesis                m=

25

Level of Significance

0.05

Sample Size

=COUNT(Sheet1!$A$1:$A$31)

Sample Mean

=AVERAGE(Sheet1!$A$1:$A$31)

Sample Standard Deviation

=STDEV.S(Sheet1!$A$1:$A$31)

Intermediate Calculations

Standard Error of the Mean

=B8/SQRT(B6)

Degrees of Freedom

=B6-1

t Test Statistic

=(B7-B4)/B11

Two-Tail Test

Lower Critical Value

=-(T.INV.2T(B5, B12))

Upper Critical Value

=T.INV.2T(B5, B12)

p-Value

=T.DIST.2T(ABS(B13), B12)

=IF(B18<$B$5, "Reject the null hypothesis", "Do not reject the null hypothesis")


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